I am using Java and trying to retrieve Call Log Records. trying to get a token for the call
Unirest.post(AuthURL);
rs.header("accept", "application/json");
rs.header("Content-Type", "application/x-www-form-urlencoded");
rs.header("Authorization", "Basic "+ClientId+ClientSecret );
parameters :
Map<String,Object> m = new HashMap<String,Object>();
m.put("grant_type", "password");
m.put("username", xxxxxx);
m.put("extension", "xxx");
m.put("password", xxxxxx);
when executed get { "errorCode" : "TokenInvalid", "message" : "Invalid token", "errors" : [ { "errorCode" : "OAU-149", "message" : "Invalid token" } ] }
Can anyone tell me the correct syntext to use for the authorization?
application https://platform.devtest.ringcentral.com/
settings as above. using the "try it" apps all works .
Is there any reason why you cannot use the official RingCentral Java SDK. It would save you lots of time.
See this dev guide on how to work with the message store.
Please refer the below blog.
https://wordpress.com/block-editor/post/khadharringcentral.home.blog/162
Since you are using password flow. the API to get the token is as follows:
url: https://platform.devtest.ringcentral.com/restapi/oauth/token
Header:
Content-Type: application/x-www-form-urlencoded
Authorization: Basic <Base64 of clientid:client secret>
Body parameter :
username=<user name>&password=<password>&extension=<extension>&grant_type=password
Please note: Here in the header Authorization will be Base64 encoding of clientid:client secret
rs.header("Authorization", "Basic "+Base64 of ClientId+":"+ ClientSecret );
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