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RegisterDevice creates a SIP device with no valid Emergency Address
Tags: developer sandbox, softphone, sip
Feb 13, 2022 at 11:59pm   •   3 replies  •  0 likes
Alex Rogers

I'm testing using the Sandbox. I would like my application to register a softphone (my own stack) so I'm trying to get and use the SIP credentials for the current logged-in user.

I call the Register Device method (https://developers.ringcentral.com/api-reference/Device-SIP-Registration/createSIPRegistration) with Transport set to UDP. This gives me the SIP credentials that I need.

Then I register my softphone. However when I make test calls with the softphone then I hear the phrase "You cannot use this phone because you have not registered your address for E911 emergency calling purposes using this phone". I do not hear this phrase when using any of the user's other devices (ie RC Phone, Yealink).

To fix it, I tried to follow up the Register with a call to Update Device (https://developers.ringcentral.com/api-reference/Devices/updateDevice) to set the Emergency Address for the device. However, this request requires me to have the "EditAccounts" privilege, and that one is not in the list that I can request.

Please can you tell me where I'm going wrong in this process?

on Feb 14, 2022 at 7:30am   •  0 likes

What is your app client id?

2 Answers
answered on Feb 14, 2022 at 1:40pm  

Are you working with BYOD devices , RC Softphone or Webphone?

One way you can add emergency address is by logging into Service Web (service.devtest.ringcentral.com) -> User -> Phone Number. - > Edit Emergency Address here:

general-settings.pnguser-phone-details.png


If you are using WebPhone -> OAuth flow has a way to update emergency address for Webphone devices .


Lemme know if that works for you



 0
on Feb 14, 2022 at 2:21pm   •  0 likes

Thanks, vyshakhbabji. I'm using a BYOB device.

The device that I create using CreateSipRegistration doesn't appear in the the portal as per your screenshot. There, I only see my two permanent devices.

1644877298883.png

answered on Feb 14, 2022 at 8:27am  

My App's Client ID is: Gg5FnfxXQVaI4qfNcttVoA


 0



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